Python Daily

What's the best way to redirect to a different view in the case of an exception?

Hi there,

I'm implementing a payment system on my site and I'm wondering what the best practice way to handle exceptions would be. The exception handling for CC processing is built into the payment processor (Stripe), so that part's not a problem. What I'm trying to determine is what's the best way for me to handle an exception if one is caught, for example a card processing error (e.g. credit card was declined).

In the view that processes the card, it takes a token returned by Stripe, tries to create a customer, assign them to a subscription, and if it fails there are a number of exceptions thrown like CardError, AuthenticationError, InvalidRequestError, etc. In those exceptions I am able to trap the error message easily (e.g. "your credit card was declined") and then return a different template, like subscribe_error.html, which can show the error as a template variable. No problem. The only problem there is that the URL still shows the thank you URL. So I really need to redirect to the error url (e.g. /subscribeerror or whatever), but keep the error message. So what's the best practice way to do this?

Basically, the error handling works, but I just don't know if I am doing it the best way I can. Here's some code:

def pro_annual_thanks(request):

token = request.POST.get('stripeToken')
email = request.POST.get('stripeEmail')
name = request.POST.get('stripeName')

customer_data = {
'description': name,
'card': token,
'email': email
}

try:
stripe.api_key = settings.STRIPE_TEST_SECRET_KEY
customer = stripe.Customer.create(**customer_data)
subscription = customer.subscriptions.create(plan="annual_pro")

except stripe.error.CardError as e:
# Since it's a decline, stripe.error.CardError will be caught
body = e.json_body
err = body.get('error', {})

print "Status is: %s" % e.http_status
print "Type is: %s" % err.get('type')
print "Code is: %s" % err.get('code')
# param is '' in this case
print "Param is: %s" % err.get('param')
print "Message is: %s" % err.get('message')

### SHOULD I REDIRECT HERE INSTEAD? ###
### HOW DO I KEEP THE ERROR MESSAGE? ###
### I HAVE A URL FOR SUBSCRIBE ERRORS IF NEEDED ###
### AND ALSO A subscribe_error(request, error) VIEW ###
template = 'subscribe_error.html'
context = {
'error' : err.get('message')
}
return render(request, template, context)

context = {
'plan' : 'Annual Pro',
'custName' : name,
'custEmail' : email
}
template = 'pro_annual_thanks.html'
return render(request, template, context)

I know a few different ways to do this, for example I could store the context in the session and then pull it from the subscribe_error() view. I could also use redirect() or HttpResponseRedirect() but I'm not sure which, or what the best practice would be.

Any tips? Thanks!

/r/django
https://redd.it/6xxoeo

What's the best way to redirect to a different view in... • r/django

Hi there, I'm implementing a payment system on my site and I'm wondering what the best practice way to handle exceptions would be. The exception...

39 views04:30